Engineering Mechanics The moment of inertia of a solid cylinder of mass 'm', radius 'r' and length 'l' about the longitudinal axis or polar axis is mr²/4 mr²/6 mr²/2 mr²/8 mr²/4 mr²/6 mr²/2 mr²/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum velocity of a particle moving with simple harmonic motion is ω/r ωr ω ω2r ω/r ωr ω ω2r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum frictional force which comes into play when a body just begins to slide over another surface is called Rolling friction Kinematic friction Limiting friction Sliding friction Rolling friction Kinematic friction Limiting friction Sliding friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the width (b), is bd³/36 db³/36 bd³/12 db³/12 bd³/36 db³/36 bd³/12 db³/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The frequency of oscillation of a compound pendulum is (where kG = Radius of gyration about the centroidal axis, and h = Distance between the point of suspension and C.G. of the body.) 1/2π. √(gh/kG² + h²) 2π. √(gh/kG² + h²) 1/2π. √(kG² + h²/gh) 2π. √(kG² + h²/gh) 1/2π. √(gh/kG² + h²) 2π. √(gh/kG² + h²) 1/2π. √(kG² + h²/gh) 2π. √(kG² + h²/gh) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
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