Engineering Mechanics The maximum efficiency of a lifting machine is m/V.R. 1/(m × V.R.) 1/m V.R./m m/V.R. 1/(m × V.R.) 1/m V.R./m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The bodies which rebound after impact are called Elastic bodies Inelastic bodies None of these Neither elastic nor inelastic bodies Elastic bodies Inelastic bodies None of these Neither elastic nor inelastic bodies ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the width (b), is db³/12 bd³/36 bd³/12 db³/36 db³/12 bd³/36 bd³/12 db³/36 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is h/(kG² + h²) (kG² + h²)/h h²/(kG² + h²) (kG² + h²)/h² h/(kG² + h²) (kG² + h²)/h h²/(kG² + h²) (kG² + h²)/h² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity of a body on reaching the ground from a height h, is √(gh) 2.√(gh) √(2gh) 2g.√h √(gh) 2.√(gh) √(2gh) 2g.√h ANSWER DOWNLOAD EXAMIANS APP
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