Engineering Mechanics The maximum efficiency of a lifting machine is m/V.R. 1/m 1/(m × V.R.) V.R./m m/V.R. 1/m 1/(m × V.R.) V.R./m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The efficiency of a lifting machine is the ratio of All of these Mechanical advantage to the velocity ratio Work done by the machine to the work done on the machine Output to the input All of these Mechanical advantage to the velocity ratio Work done by the machine to the work done on the machine Output to the input ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The center of percussion of a solid cylinder of radius ‘r’ resting on a horizontal plane will be r/2 3r/2 r/A 2r/3 r/2 3r/2 r/A 2r/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A particle inside a hollow sphere of radius r, having coefficient of friction µ can rest up to height of r/3 r/A r/2 0.134 r r/3 r/A r/2 0.134 r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One joule means that Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 dyne when it displaces a body through 1 cm ANSWER DOWNLOAD EXAMIANS APP
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