Engineering Mechanics If tension in the cable supporting a lift moving downwards is half the tension when it is moving upwards, the acceleration of the lift is g/2 None of these g/4 g/3 g/2 None of these g/4 g/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Non-coplanar non-concurrent forces are those forces which Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane None of these Do not meet at one point but their lines of action lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane None of these Do not meet at one point but their lines of action lie on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of a right circular solid cone is at a distance of _________ from its base, measured along the vertical axis.(where h = Height of a right circular solid cone.) h/6 h/2 h/4 h/3 h/6 h/2 h/4 h/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Whenever a force acts on a body and the body undergoes a displacement, then Body has kinetic energy of translation None of these Work is said to be done Power is being transmitted Body has kinetic energy of translation None of these Work is said to be done Power is being transmitted ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The potential energy of a vertically raised body is __________ the kinetic energy of a vertically falling body. None of these Less than Equal to Greater than None of these Less than Equal to Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP