Engineering Mechanics A force while acting on a body may Change its motion All of these Give rise to the internal stresses in it Balance the forces, already acting on it Change its motion All of these Give rise to the internal stresses in it Balance the forces, already acting on it ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A ladder is resting on a smooth ground and leaning against a rough vertical wall. The force of friction will act Upward at its upper end Towards the wall at its upper end Downward at its upper end Away from the wall at its upper end Upward at its upper end Towards the wall at its upper end Downward at its upper end Away from the wall at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A machine having an efficiency less than 50%, is known as Reversible machine Non-reversible machine Ideal machine Neither reversible nor non-reversible machine Reversible machine Non-reversible machine Ideal machine Neither reversible nor non-reversible machine ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/8 bh3/36 bh3/4 bh3/12 bh3/8 bh3/36 bh3/4 bh3/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Angle of friction is the Angle between normal reaction and the resultant of normal reaction and the limiting friction The ratio of minimum friction force to friction force acting when the body is in motion Ratio of limiting friction and normal reaction The ratio of minimum friction force to the friction force acting when the body is just about to move Angle between normal reaction and the resultant of normal reaction and the limiting friction The ratio of minimum friction force to friction force acting when the body is in motion Ratio of limiting friction and normal reaction The ratio of minimum friction force to the friction force acting when the body is just about to move ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
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