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Engineering Mechanics

Engineering Mechanics
Moment of inertia of a circular section about its diameter (d) is

πd4/32
πd3/16
πd3/32
πd4/64

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Engineering Mechanics
The resultant of the two forces ‘P’ and ‘Q’ is ‘R’. If ‘Q’ is doubled, the new resultant is perpendicular to ‘P’. Then

P = Q
None of the listed here
Q = R
Q = 2R

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Engineering Mechanics
On a ladder resting on smooth ground and leaning against vertical wall, the force of friction will be

Upwards at its upper end
Downwards at its upper end
Away from the wall at its upper end
Towards the wall at its upper end

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Engineering Mechanics
The motion of a wheel of a car is

Combined translation and rotational
None of the listed here
Purely translation
Purely rotational

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Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = Ah2 / IG
IP = IG / Ah2
IP = IG + Ah2
IP = IG - Ah2

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Engineering Mechanics
The C.G. of a solid hemisphere lies on the central radius 3r

At distance — from the plane base 3r
At distance — from the plane base 3r
At distance — from the plane base
At distance — from the plane base 3r

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