Engineering Mechanics Moment of inertia of a circular section about its diameter (d) is πd4/64 πd3/32 πd4/32 πd3/16 πd4/64 πd3/32 πd4/32 πd3/16 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following is an equation of linear motion?(where, u and v = Initial and final velocity of the body, a = Acceleration of the body, and s = Displacement of the body in time t seconds.) v2 = u2 + 2a.s s = u.t + ½ a.t2 v = u + a.t All of these v2 = u2 + 2a.s s = u.t + ½ a.t2 v = u + a.t All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A machine having an efficiency less than 50%, is known as Reversible machine Non-reversible machine Ideal machine Neither reversible nor non-reversible machine Reversible machine Non-reversible machine Ideal machine Neither reversible nor non-reversible machine ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a differential wheel and axle with 'D' as the diameter of effort wheel and d1 and d2 as the diameters of larger and smaller axles respectively, is 2D/(d₁ - d₂) D/(d₁ + d₂) D/(d₁ - d₂) 2D/(d₁ + d₂) 2D/(d₁ - d₂) D/(d₁ + d₂) D/(d₁ - d₂) 2D/(d₁ + d₂) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One kg force is equal to 9.8 N 8.9 N 7.8 N 12 N 9.8 N 8.9 N 7.8 N 12 N ANSWER DOWNLOAD EXAMIANS APP
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