Engineering Mechanics
A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is

2v
8v
4v
v

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics
The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)

y = x. tanα - (gx²/2u² cos²α)
y = (gx²/2u² cos²α) - x. tanα
y = x. tanα + (gx²/2u² cos²α)
y = (gx²/2u² cos²α) + x. tanα

ANSWER DOWNLOAD EXAMIANS APP