Engineering Mechanics If the gravitational acceleration at any place is doubled, then the weight of a body will be g 2g g/2 √2.g g 2g g/2 √2.g ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The three forces of 100 N, 200 N and 300 N have their lines of action parallel to each other but act in the opposite directions. These forces are known as Like parallel forces Coplanar concurrent forces Coplanar non-concurrent forces Unlike parallel forces Like parallel forces Coplanar concurrent forces Coplanar non-concurrent forces Unlike parallel forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The force applied on a body of mass 100 kg to produce an acceleration of 5 m/s2, is None of these 500 N 20 N 100 N None of these 500 N 20 N 100 N ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The mechanical advantage of a lifting machine is the ratio of All of these Distance moved by effort to the distance moved by load Load lifted to the effort applied Output to the input All of these Distance moved by effort to the distance moved by load Load lifted to the effort applied Output to the input ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The law of the machine is (where P = Effort applied to lift the load, m = A constant which is equal to the slope of the line, W = Load lifted, and C = Another constant which represents the machine friction.) P = mW + C P = mW - C P = C - mW P = m/W + C P = mW + C P = mW - C P = C - mW P = m/W + C ANSWER DOWNLOAD EXAMIANS APP
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