Engineering Mechanics The moment of inertia of a thin rod of mass 'm' and length 'l', about an axis through its centre of gravity and perpendicular to its length is ml2/ 6 ml2/8 ml2/4 ml2/12 ml2/ 6 ml2/8 ml2/4 ml2/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.) P = W (sinα + μcosα) P = W tanα P = W (cosα + μsinα) P = W tan (α + φ) P = W (sinα + μcosα) P = W tanα P = W (cosα + μsinα) P = W tan (α + φ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The mechanical advantage of a lifting machine is the ratio of All of these Distance moved by effort to the distance moved by load Output to the input Load lifted to the effort applied All of these Distance moved by effort to the distance moved by load Output to the input Load lifted to the effort applied ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics For a self locking machine, the efficiency must be Equal to 50% Greater than 50% 1 Less than 50% Equal to 50% Greater than 50% 1 Less than 50% ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics On a ladder resting on smooth ground and leaning against vertical wall, the force of friction will be Away from the wall at its upper end Upwards at its upper end Towards the wall at its upper end Downwards at its upper end Away from the wall at its upper end Upwards at its upper end Towards the wall at its upper end Downwards at its upper end ANSWER DOWNLOAD EXAMIANS APP
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