Engineering Mechanics The unit of moment of inertia of an area is kg/m2 m4 kg-m2 kg-m-s2 kg/m2 m4 kg-m2 kg-m-s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A trolley wire weighs 1.2 kg per meter length. The ends of the wire are attached to two poles 20 meters apart. If the horizontal tension is 1500 kg find the dip in the middle of the span 5.0 cm 2.5 cm 3.0 cm 4.0 cm 5.0 cm 2.5 cm 3.0 cm 4.0 cm ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is v 2v 4v 8v v 2v 4v 8v ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a simple wheel and axle with D and d as the diameters of effort wheel and load axle, is D / d D - d D × d D + d D / d D - d D × d D + d ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the gravitational acceleration at any place is doubled, then the weight of a body will be g/2 2g g √2.g g/2 2g g √2.g ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS