Engineering Mechanics The maximum mechanical advantage of a lifting machine is 1 / m m 1 - m 1 + m 1 / m m 1 - m 1 + m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the depth (d), is db³/12 bd³/12 bd³/36 db³/36 db³/12 bd³/12 bd³/36 db³/36 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The C.G. of a solid hemisphere lies on the central radius 3r At distance — from the plane base 3r At distance — from the plane base At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base At distance — from the plane base 3r At distance — from the plane base 3r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear acceleration (a) of a body rotating along a circular path of radius (r) with an angular acceleration of α rad/s2, is a = r / α a = α/ r None of these a = α.r a = r / α a = α/ r None of these a = α.r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/36 a4/8 a4/12 a4/4 a4/36 a4/8 a4/12 a4/4 ANSWER DOWNLOAD EXAMIANS APP
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