Engineering Mechanics The time of flight (t) of a projectile on an upward inclined plane is(where u = Velocity of projection, α = Angle of projection, and β = Inclination of the plane with the horizontal.) t = 2u sin (α + β)/g cos β t = g cos β/2u sin (α - β) t = g cos β/2u sin (α + β) t = 2u sin (α - β)/g cos β t = 2u sin (α + β)/g cos β t = g cos β/2u sin (α - β) t = g cos β/2u sin (α + β) t = 2u sin (α - β)/g cos β ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/12 bh3/8 bh3/36 bh3/4 bh3/12 bh3/8 bh3/36 bh3/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about an axis perpendicular to the section is πd3/32 πd3/16 πd4/32 πd4/64 πd3/32 πd3/16 πd4/32 πd4/64 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The coefficient of restitution for inelastic bodies is Zero Between zero and one More than one One Zero Between zero and one More than one One ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight of a projectile on downward inclined plane depends upon Angle of projection Angle of inclination of the plane None of these Both (A) and (B) Angle of projection Angle of inclination of the plane None of these Both (A) and (B) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
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