Engineering Mechanics A particle moves along a straight line such that distance (x) traversed in 't' seconds is given by x = t² (t - 4), the acceleration of the particle will be given by the equation 6f - 8 6f - 4 3t² + 2t 6t² - 8t 6f - 8 6f - 4 3t² + 2t 6t² - 8t ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A framed structure is imperfect, if the numbers of members are __________ (2j - 3). Less than Equal to Greater than Either (B) or (C) Less than Equal to Greater than Either (B) or (C) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the width (b), is db³/12 bd³/12 bd³/36 db³/36 db³/12 bd³/12 bd³/36 db³/36 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is 8v 4v v 2v 8v 4v v 2v ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
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