Engineering Mechanics On the ladder resting on the ground and leaning against a smooth vertical wall, the force of friction will be Upwards at its upper end Downwards at its upper end Perpendicular to the wall at its upper end Zero at its upper end Upwards at its upper end Downwards at its upper end Perpendicular to the wall at its upper end Zero at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio for the third system of pulleys is 2n - 1 n 2n n² 2n - 1 n 2n n² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) is 60° + β/2 45° + β/2 30° + β/2 β/2 60° + β/2 45° + β/2 30° + β/2 β/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces which do not meet at one point and their lines of action do not lie on the same plane are known as Coplanar non-concurrent forces None of these Non-coplanar concurrent forces Coplanar concurrent forces Coplanar non-concurrent forces None of these Non-coplanar concurrent forces Coplanar concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of an isosceles triangle with base (p) and sides (q) from its base is (4p² - q²)/6 (p² - q²)/4 (p² + q²)/4 [√(4p² - q²)]/6 (4p² - q²)/6 (p² - q²)/4 (p² + q²)/4 [√(4p² - q²)]/6 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
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