Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of two equal forces ‘P’ making an angle ‘θ’, is given by 2P cotθ/2 2P cosθ/2 2P sinθ/2 2P tanθ/2 2P cotθ/2 2P cosθ/2 2P sinθ/2 2P tanθ/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of coplanar forces acting at a point be in equilibrium, the sum of clockwise moments must be __________ the sum of anticlockwise moments, about any point. Less than Greater than Equal to None of these Less than Greater than Equal to None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/12 a4/4 a4/36 a4/8 a4/12 a4/4 a4/36 a4/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the gravitational acceleration at any place is doubled, then the weight of a body will be √2.g g 2g g/2 √2.g g 2g g/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A ladder is resting on a smooth ground and leaning against a rough vertical wall. The force of friction will act Towards the wall at its upper end Upward at its upper end Downward at its upper end Away from the wall at its upper end Towards the wall at its upper end Upward at its upper end Downward at its upper end Away from the wall at its upper end ANSWER DOWNLOAD EXAMIANS APP
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