Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The range of projectile (R) on an upward inclined plane is g. cos² β/2u². sin (α - β). cos α 2u². sin (α + β). cos α/g. cos² β 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α + β). cos α g. cos² β/2u². sin (α - β). cos α 2u². sin (α + β). cos α/g. cos² β 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α + β). cos α ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The force, by which the body is attracted, towards the center of the earth, is called Mass Impulsive force Weight Momentum Mass Impulsive force Weight Momentum ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a body of mass moment of inertia 'I' (about a given axis) is rotated about that axis with an angular velocity to, then the kinetic energy of rotation is 0.5 Iω Iω2 0.5 Iω2 Iω 0.5 Iω Iω2 0.5 Iω2 Iω ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The center of gravity of a quadrant of a circle lies along its central radius (r) at a distance of 0.6 r 0.7 r 0.5 r 0.8 r 0.6 r 0.7 r 0.5 r 0.8 r ANSWER DOWNLOAD EXAMIANS APP
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