Engineering Mechanics The mechanical advantage of a lifting machine is the ratio of Load lifted to the effort applied Output to the input Distance moved by effort to the distance moved by load All of these Load lifted to the effort applied Output to the input Distance moved by effort to the distance moved by load All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of an isosceles triangle with base (p) and sides (q) from its base is [√(4p² - q²)]/6 (p² + q²)/4 (4p² - q²)/6 (p² - q²)/4 [√(4p² - q²)]/6 (p² + q²)/4 (4p² - q²)/6 (p² - q²)/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics For any system of coplanar forces, the condition of equilibrium is that the Algebraic sum of the vertical components of all the forces should be zero Algebraic sum of the horizontal components of all the forces should be zero Algebraic sum of moments of all the forces about any point should be zero All of these Algebraic sum of the vertical components of all the forces should be zero Algebraic sum of the horizontal components of all the forces should be zero Algebraic sum of moments of all the forces about any point should be zero All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of two equal forces ‘P’ making an angle ‘θ’, is given by 2P cotθ/2 2P tanθ/2 2P cosθ/2 2P sinθ/2 2P cotθ/2 2P tanθ/2 2P cosθ/2 2P sinθ/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of a uniform lamina lies at The centre of heavy portion The bottom surface All of these The midpoint of its axis The centre of heavy portion The bottom surface All of these The midpoint of its axis ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
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