Engineering Mechanics A screw jack used for lifting the loads is None of these A reversible machine An ideal machine A non-reversible machine None of these A reversible machine An ideal machine A non-reversible machine ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The principle of transmissibility of forces states that, when a force acts upon a body, its effect is Different at different points on its line of action Same at every point on its line of action Minimum, if it acts at the center of gravity of the body Maximum, if it acts at the center of gravity of the body Different at different points on its line of action Same at every point on its line of action Minimum, if it acts at the center of gravity of the body Maximum, if it acts at the center of gravity of the body ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are 15 N and 5 N 20 N and 5 N 15 N and 15 N None of these 15 N and 5 N 20 N and 5 N 15 N and 15 N None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lift the load is given by (where W = Load lifted, α = Helix angle, and φ = Angle of friction.) P = W cos (α + φ) P = W tan (α + φ) P = W tan (φ - α) P = W tan (α - φ) P = W cos (α + φ) P = W tan (α + φ) P = W tan (φ - α) P = W tan (α - φ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The total momentum of a system of masses (i. e. moving bodies) in any one direction remains constant, unless acted upon by an external force in that direction. This statement is called Newton's first law of motion Principle of conservation of energy Newton's second law of motion Principle of conservation of momentum Newton's first law of motion Principle of conservation of energy Newton's second law of motion Principle of conservation of momentum ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a differential pulley block with D and d as the diameters of larger and smaller pulley, is 2D/(D + d) 2D/(D - d) D/(D - d) D/(D + d) 2D/(D + d) 2D/(D - d) D/(D - d) D/(D + d) ANSWER DOWNLOAD EXAMIANS APP
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