Theory of Machine The maximum or minimum value of the swaying couple is ± (a/√2) (1 - c) m.ω².r ± c.m.ω².r ± 2a (1 - c) m.ω².r ± a (1 - c) m.ω².r ± (a/√2) (1 - c) m.ω².r ± c.m.ω².r ± 2a (1 - c) m.ω².r ± a (1 - c) m.ω².r ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Sensitiveness of the governor is defined as the ratio of the Difference of the maximum and minimum equilibrium speeds to the mean speed Sum of the maximum and minimum equilibrium speeds to the mean speed Mean speed to the minimum equilibrium speed Mean speed to the maximum equilibrium speed Difference of the maximum and minimum equilibrium speeds to the mean speed Sum of the maximum and minimum equilibrium speeds to the mean speed Mean speed to the minimum equilibrium speed Mean speed to the maximum equilibrium speed ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A spring controlled governor is said to be stable if the controlling force line when produced intersects the Y-axis At the origin Any one of these Above the origin Below the origin At the origin Any one of these Above the origin Below the origin ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A Hartnell governor is a Spring loaded governor Pendulum type governor Inertia governor Dead weight governor Spring loaded governor Pendulum type governor Inertia governor Dead weight governor ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Grubler's criterion for determining the degrees of freedom (n) of a mechanism having plane motion is (where l = Number of links, and j = Number of binary joints) n = 4(l - 1) - 3j n = 2(l - 1) - 2j n = (l -1) - j n = 3(l - 1) - 2j n = 4(l - 1) - 3j n = 2(l - 1) - 2j n = (l -1) - j n = 3(l - 1) - 2j ANSWER DOWNLOAD EXAMIANS APP
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