Theory of Machine The main disadvantage of the sliding pair is that it is Wears rapidly Bulky Difficult to manufacture Both (A) and (B) above Wears rapidly Bulky Difficult to manufacture Both (A) and (B) above ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Bifilar suspension method is used to find the Frequency of vibration of the body Periodic time of the body Moment of inertia of the body Angular acceleration of the body Frequency of vibration of the body Periodic time of the body Moment of inertia of the body Angular acceleration of the body ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The acceleration of a particle at any instant has two components i.e. radial component and tangential component. These two components will be Inclined at 45° Opposite to each other Parallel to each other Perpendicular to each other Inclined at 45° Opposite to each other Parallel to each other Perpendicular to each other ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The engine of an aeroplane rotates in clockwise direction when seen from the tail end and the aeroplane takes a turn to the left. The effect of gyroscopic couple on the aeroplane will be To dip the nose and raise the tail To dip the nose and tail To raise the nose and dip the tail To raise the nose and tail To dip the nose and raise the tail To dip the nose and tail To raise the nose and dip the tail To raise the nose and tail ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The fundamental equation for correct steering is (where φ and α = Angle through which the axis of the outer wheel and inner wheel turns respectively, c = Distance between the pivots of the front axles, and d = Wheel base) cotφ - cotα = c/b sinφ + sinα = b/c cosφ - sinα = c/b tanφ + cotα = b/c cotφ - cotα = c/b sinφ + sinα = b/c cosφ - sinα = c/b tanφ + cotα = b/c ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Grubler's criterion for determining the degrees of freedom (n) of a mechanism having plane motion is (where l = Number of links, and j = Number of binary joints) n = (l -1) - j n = 3(l - 1) - 2j n = 2(l - 1) - 2j n = 4(l - 1) - 3j n = (l -1) - j n = 3(l - 1) - 2j n = 2(l - 1) - 2j n = 4(l - 1) - 3j ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS