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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

40
64
28
32

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is:

48
84
12
108

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

31/45
17/29
11/13
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively.

3024
3013
3002
3036

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The product of two digits number is 2160 and their HCF is 12. The numbers are:

(12,180)
(96,25)
(72,30)
(36,60)

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

2683
4683
3683
1683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5,6,7,8 = 840.    Required number is of the form 840k + 3     Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683

MORE MCQ ON Problems on H.C.F and L.C.M

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