Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 28 32 64 40 28 32 64 40 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers. 8 and 6 2 and 4 6 and 4 8 and 10 8 and 6 2 and 4 6 and 4 8 and 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 606 505 404 707 606 505 404 707 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10010 10080 10015 10020 10010 10080 10015 10020 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 9720 8720 6720 7720 9720 8720 6720 7720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: 1 F Cannot be calculated equal to their H. 117 1 F Cannot be calculated equal to their H. 117 ANSWER DOWNLOAD EXAMIANS APP
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