Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 180 1260 540 360 180 1260 540 360 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 770 420 540 630 770 420 540 630 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
Problems on H.C.F and L.C.M What is the smallest number which when diminished by 8, is divisible by 9, 6, 12 and 18? 60 45 50 44 60 45 50 44 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 172, 205 and 304 so as to leave the same remainder in each case? 99 66 None of these 33 99 66 None of these 33 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The greatest number that will divide 172,205 and 304 leaving the same remainder in each case is HCF ((205-172), (304-205), (304-172)) = HCF of 33, 99, and 132 33=31x11 99=3 x 3 x 11 132=3 x 2 x 2 x11 Required number =3 x 11=33
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: 117 Cannot be calculated equal to their H. F 1 117 Cannot be calculated equal to their H. F 1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 5 : 27 : 12 hrs. 8 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. 8 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
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