Hydraulics and Fluid Mechanics in ME The kinematic viscosity of an oil (in stokes) whose specific gravity is 0.95 and viscosity 0.011 poise, is 0.0116 stoke 0.0611 stoke 0.116 stoke 0.611 stoke 0.0116 stoke 0.0611 stoke 0.116 stoke 0.611 stoke ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In an immersed body, centre of pressure is Above the centre of gravity Below be centre of gravity At the centre of gravity Could be above or below e.g. depending on density of body and liquid Above the centre of gravity Below be centre of gravity At the centre of gravity Could be above or below e.g. depending on density of body and liquid ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In an immersed body, center of pressure is below be center of gravity could be above or below e.g. depending on density of body and liquid at the center of gravity above the center of gravity below be center of gravity could be above or below e.g. depending on density of body and liquid at the center of gravity above the center of gravity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Metacentric height for small values of angle of heel is the distance between the centre of buoyancy and metacentre free surface and centre of buoyancy centre of gravity and centre of buoy-ancy centre of gravity and metacentre centre of buoyancy and metacentre free surface and centre of buoyancy centre of gravity and centre of buoy-ancy centre of gravity and metacentre ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A moving fluid mass may be brought to a static equilibrium position, by applying an imaginary inertia force of the same magnitude as that of the accelerating force but in the opposite direction. This statement is called None of these Archimedes’s principle Pascal’s law D-Alembert’s principle None of these Archimedes’s principle Pascal’s law D-Alembert’s principle ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The torque required to overcome viscous resistance of a collar bearing is (where R1 and R2 = External and internal radius of collar) (μπ²N/60t) × (R₁ - R₂) (μπ²N/60t) × (R₁² - R₂²) μπ²N/60t) × (R₁³ - R₂³) (μπ²N/60t) × (R₁⁴ - R₂⁴) (μπ²N/60t) × (R₁ - R₂) (μπ²N/60t) × (R₁² - R₂²) μπ²N/60t) × (R₁³ - R₂³) (μπ²N/60t) × (R₁⁴ - R₂⁴) ANSWER DOWNLOAD EXAMIANS APP
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