MGVCL Exam Paper (30-07-2021 Shift 2) The Great Barrier Reef is located in which country? Australia Canada Germany India Australia Canada Germany India ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance. (IRcosφ_r + IXsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + IXsinφ)/V_rFor leading power factor = (IR*cosφ - IXsinφ)/V_rZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Amino Intersect Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome Acquired Immune Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 12 kV, 50 Hz and 300 kW load is operating at 0.8 pf lag. If the pf is to be improved to unity, using star connected capacitor, the per phase value of the reactive VAR required is: 50 kVAR 75 kVAR 100 kVAR 25 kVAR 50 kVAR 75 kVAR 100 kVAR 25 kVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The reactive VAR required = kW*(tanφ1 -tanφ2)Cosφ1 = 0.8φ1 = 36.87 deg.Cosφ2 = 0φ2 = 0 deg.kVAR required = kW*(tan(36.87) - tan(0))= 300*1000(0.75)= 225.00 kVARPer phase value = 225.00/3= 75 kVAR
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 620 kVA 1240 kVA 2480 kVA 930 kVA 620 kVA 1240 kVA 2480 kVA 930 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA
MGVCL Exam Paper (30-07-2021 Shift 2) Who started the daily newspaper 'National Herald' in 1938? Subhas Chandra Bose Jawaharlal Nehru Dadabhai Naoroji Ram Mohan Roy Subhas Chandra Bose Jawaharlal Nehru Dadabhai Naoroji Ram Mohan Roy ANSWER DOWNLOAD EXAMIANS APP
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