MGVCL Exam Paper (30-07-2021 Shift 2)
A single phase motor connected to 415 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging.
The capacity of reactor = 50 MVAr when it is operated at 415 kV. Impedance of reactor = V2/MVAr = (415*415)2/50 = 3444.5 Ω For 400 kV, Reactive power observed = (400*400)/3444.5 = 46.45 MVAR
Or
VAr capacity of capacitor or reactor is proportional to V²
At no load the solar cell will be operating in open circuit condition. If there is internal shunting resistance it will slightly load the solar cell. This shunt resistance must be high enough such that it will not cause an appreciable loss of the photo voltaic power.