Theory of Machine The fundamental equation for correct steering is (where φ and α = Angle through which the axis of the outer wheel and inner wheel turns respectively, c = Distance between the pivots of the front axles, and d = Wheel base) cosφ - sinα = c/b tanφ + cotα = b/c cotφ - cotα = c/b sinφ + sinα = b/c cosφ - sinα = c/b tanφ + cotα = b/c cotφ - cotα = c/b sinφ + sinα = b/c ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat pivot bearing, assuming uniform wear, is(Where μ = Coefficient of friction, W=Load over the bearing, R=Radius of bearing) ½μWR μwr ¾μWR ²/₃ μWR ½μWR μwr ¾μWR ²/₃ μWR ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Lower pairs are those which have Elements of pairs not held together mechanically Surface contact between the two elements when in motion Point or line contact between the two elements when in motion Two elements that permit relative motion Elements of pairs not held together mechanically Surface contact between the two elements when in motion Point or line contact between the two elements when in motion Two elements that permit relative motion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r (sin 2θ/n) m.ω².r cosθ m.ω².r (cos 2θ/n) m.ω².r sinθ m.ω².r (sin 2θ/n) m.ω².r cosθ m.ω².r (cos 2θ/n) m.ω².r sinθ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The relation between the controlling force (Fc) and radius of rotation (r) for a stable spring controlled governor is Fc = ar - b Fc = ar + b Fc = a/r + b Fc = ar Fc = ar - b Fc = ar + b Fc = a/r + b Fc = ar ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a disc clutch, if there are n₁ number of discs on the driving shaft and n₂ number of discs on the driven shaft, then the number of pairs of contact surfaces will be n₁ + n₂ - 1 n₁ + n₂ + 1 n₁ + n₂ - 2 n₁ + n₂ n₁ + n₂ - 1 n₁ + n₂ + 1 n₁ + n₂ - 2 n₁ + n₂ ANSWER DOWNLOAD EXAMIANS APP
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