SSC JE Electrical 2019 with solution SET-1 The function of condenser in a Thermal power plant is: Condense used steam into water Purify water Purify steam Condense water Condense used steam into water Purify water Purify steam Condense water ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 The below symbol which is used in single line diagrams represents Current transformer Circuit breaker Power transformer Potential transformer Current transformer Circuit breaker Power transformer Potential transformer ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 Identify the machine shown in the circuit DC short shunt compound generator DC long shunt compound generator DC shunt motor DC short shunt compound motor DC short shunt compound generator DC long shunt compound generator DC shunt motor DC short shunt compound motor ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 ________ is used to manufacture stay wire, earth wire, and structural components Cadmium copper Nichrome Hard drawn copper Galvanized steel Cadmium copper Nichrome Hard drawn copper Galvanized steel ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Galvanized steel conductors do not corrode, and possess high resistance. Hence such Wires are used in telecommunications circuits, earth wires, guard wire, stray wire, etc.
SSC JE Electrical 2019 with solution SET-1 Extension of moving iron ammeter range can be done by using Shunt Capacitor Inductor Multiplier Shunt Capacitor Inductor Multiplier ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 In an AC network, the load connected is (10 + j10). The phase relation between the voltage applied and the current through the load is: Voltage lags current by 30° Voltage and current are in phase with each other Voltage lags current by 45° Voltage leads current by 45° Voltage lags current by 30° Voltage and current are in phase with each other Voltage lags current by 45° Voltage leads current by 45° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L0ad impedance Z = R + jXz = 10 + 10jPhase angle θ= tan−1(IL/IR)θ= tan−1(10/10)tanθ = 1tanθ =45°
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