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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 The power factor of an A.C. circuit is equal to

R/Z
R/XL
Z/R
R/XC

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In electrical engineering, the power factor of an AC electrical power system is defined as the ratio of the real power flowing to the load to the apparent power in the circuit ” R/Z”.
 

SSC JE Electrical 2019 with solution SET-1
 Relate ‘Reluctance with the following:

A/m
Weber/m
A-T/Weber
Weber/A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The reluctance of any part of a magnetic circuit may be defined as the ratio of the drop in magnetomotive force to the flux produced in that part of the circuit. It is measured in ampere-turns/Weber and is denoted by S.
Reluctance = m.m.f ⁄ flux 
 

SSC JE Electrical 2019 with solution SET-1
 A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil

0.25 mH
1.25 mH
2.5 mH
0.125 mH

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The inductance of the coil is given by the relation
L = Nφ/I
Where
N = number of turns = 50
φ = flux = 200μWb
I = current = 8 A
L = 50 × 200 ×  10−6 ⁄ 8
L = 1.25 mH

SSC JE Electrical 2019 with solution SET-1
 Identify the important feature of a DC series motor

High starting torque
Low starting torque
Zero starting torque
Medium starting torque

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.

SSC JE Electrical 2019 with solution SET-1
 A 200 V d.c machine as Ra = 0.5 Ω and its full-load Ia= 20A. Determine the induced e.m.f when the machine acts as a motor

190 V
215 V
200 V
210 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given Data
Voltage Va = 200 v
Armature Resistance Ra = 0.5Ω
Armature Current Ia = 20 A
Induced EMF = Ea = ?
The Induced EMF of a DC machine working as a Motor is
Ea = Va − IaRa
Ea = 200 − 20 × 0.5
Ea = 190 V

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, the pressure coils of two wattmeters are connected to

R
Neutral Wire
Y
B

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In Two wattmeter method the current coils of the wattmeter are connected with any two lines, say R and Y and the potential coil of each wattmeter is joined across the same line, the third line i.e. B as shown below in the figure . In the circuit B is the common point for both the wattmeter.

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