SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
4A
12A
120A

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SSC JE Electrical 2019 with solution SET-1
 In an AC network, the load connected is (10 + j10). The phase relation between the voltage applied and the current through the load is:

Voltage lags current by 30°
Voltage leads current by 45°
Voltage lags current by 45°
Voltage and current are in phase with each other

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SSC JE Electrical 2019 with solution SET-1
 The amount of AC content present in the DC output of a rectifier is given by

Power factor
Peak factor
Form factor
Ripple factor

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