SSC JE Electrical 2019 with solution SET-1 Find the mutual inductance between two ideally coupled coils of 2H and 8H 4 H 2 H 8 H 16 H 4 H 2 H 8 H 16 H ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance between the two coils is K = √L1.L2K = √2 × 8k = √16k = 4 H
SSC JE Electrical 2019 with solution SET-1 The below symbol which is used in single line diagrams represents Current transformer Potential transformer Circuit breaker Power transformer Current transformer Potential transformer Circuit breaker Power transformer ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 In the full-wave rectifier circuit shown in the figure, the diodes that conduct when the positive half-wave of AC signal applied are D3, D4 D2, D3 D1, D2 D4, D1 D3, D4 D2, D3 D1, D2 D4, D1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP During the positive half cycle of the supply, diodes D1 and D2 conduct are forward biased and conduct current while diodes D3 and D4 are reverse biased and they act as an open circuit, the current flows through the load.
SSC JE Electrical 2019 with solution SET-1 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches Cos 30° Cos 10° Cos 60° Cos 45° Cos 30° Cos 10° Cos 60° Cos 45° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Coil Span = 8Pole Pitch = 9 slots/poleSlot angle (α) = 180° / Pole Pitch = 180°/9 = 20°Pitch Factor = cos(α/2) = cos (20/2)Pitch Factor = cos 10°
SSC JE Electrical 2019 with solution SET-1 Identify the important feature of a DC series motor High starting torque Medium starting torque Low starting torque Zero starting torque High starting torque Medium starting torque Low starting torque Zero starting torque ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.
SSC JE Electrical 2019 with solution SET-1 With the current direction marked in the circuit shown, the net voltage applied is −(V2 − V1) V2 (V2 − V1) V1 −(V2 − V1) V2 (V2 − V1) V1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Net voltage = −V2 + V1Net voltage = −(V2 − V1)
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