SSC JE Electrical 2019 with solution SET-1 ______ Opposes the change in circuit voltage Resistance Capacitance Inductive reactance Inductance Resistance Capacitance Inductive reactance Inductance ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 An electric motor in which both the rotor and stator fields rotate with the same speed is called Induction motor DC motor Universal motor Synchronous motor Induction motor DC motor Universal motor Synchronous motor ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the synchronous motor, the stator and rotor rotate at the same speed.
SSC JE Electrical 2019 with solution SET-1 When the supply to the excitation fails, the synchronous generator acts like a/an Induction generator Synchronous motor Synchronous generator Induction motor Induction generator Synchronous motor Synchronous generator Induction motor ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 Two decimal coils A and B of 1000 turns each lies in the parallel plane such that 80% of the flux produced by one coil links with the other. If a current of 5A flowing in A produces a flux of 0.05 mWb, then the flux linking with coil B is: 0.004 mWb 0.04 mWb 4 mWb 0.4 mWb 0.004 mWb 0.04 mWb 4 mWb 0.4 mWb ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Flux in coil A = 0.05 mWb = 5 × 10−5 wb = φANo. of turns NA = NB = 1000Flux linkage in a coil with B = Flux linkage in coil A × 80/100= 0.8 × 5 × 10−5= 4 × 10−5 wb =0.04 mwb
SSC JE Electrical 2019 with solution SET-1 Extension of moving iron ammeter range can be done by using Multiplier Inductor Shunt Capacitor Multiplier Inductor Shunt Capacitor ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 With the current direction marked in the circuit shown, the net voltage applied is −(V2 − V1) V1 V2 (V2 − V1) −(V2 − V1) V1 V2 (V2 − V1) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Net voltage = −V2 + V1Net voltage = −(V2 − V1)
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