SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

1 Ω

2 Ω

10 Ω

5 Ω

1 Ω

2 Ω

10 Ω

5 Ω

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SSC JE Electrical 2019 with solution SET-1
Find the mutual inductance between two ideally coupled coils of 2H and 8H

4 H

8 H

16 H

2 H

4 H

8 H

16 H

2 H

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SSC JE Electrical 2019 with solution SET-1
A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

−4 V

0.4 V

−2.5 V

−10 V

−4 V

0.4 V

−2.5 V

−10 V

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SSC JE Electrical 2019 with solution SET-1
In an AC network, the load connected is (10 + j10). The phase relation between the voltage applied and the current through the load is:

Voltage lags current by 45°

Voltage lags current by 30°

Voltage and current are in phase with each other

Voltage leads current by 45°

Voltage lags current by 45°

Voltage lags current by 30°

Voltage and current are in phase with each other

Voltage leads current by 45°

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SSC JE Electrical 2019 with solution SET-1
With the current direction marked in the circuit shown, the net voltage applied is

V2

V1

−(V2 − V1)

(V2 − V1)

V2

V1

−(V2 − V1)

(V2 − V1)

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SSC JE Electrical 2019 with solution SET-1
P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is:

Square meter per second

Meter per second

Cubic meter per second

Meter per hour

Square meter per second

Meter per second

Cubic meter per second

Meter per hour

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