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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches

Cos 60°
Cos 45°
Cos 30°
Cos 10°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Coil Span = 8
Pole Pitch = 9 slots/pole
Slot angle (α) = 180° / Pole Pitch = 180°/9 = 20°
Pitch Factor = cos(α/2) = cos (20/2)
Pitch Factor = cos 10°
 

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Resistance
Capacitance
Inductive reactance
Inductance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil

2.5 mH
1.25 mH
0.25 mH
0.125 mH

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The inductance of the coil is given by the relation
L = Nφ/I
Where
N = number of turns = 50
φ = flux = 200μWb
I = current = 8 A
L = 50 × 200 ×  10−6 ⁄ 8
L = 1.25 mH

SSC JE Electrical 2019 with solution SET-1
 In the circuit shown, if R = 0, then the phase angle between v(t) and i(t) is

0°
60°
90°
30°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In the given circuit if R = 0 then the circuit becomes purely inductive. So the phase angle between v(t) and i(t) is 90°.


SSC JE Electrical 2019 with solution SET-1
 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

−10 V
−4 V
0.4 V
−2.5 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Inductance L = 2 H
Rate of change of current di/dt = 5 A/sec
Self induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)
= −(5 × 2) = −10V
 

SSC JE Electrical 2019 with solution SET-1
 Find the mutual inductance between two ideally coupled coils of 2H and 8H

8 H
16 H
4 H
2 H

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Mutual inductance between the two coils is K = √L1.L2
K = √2 × 8
k = √16
k = 4 H
 

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