SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

1200 W
1600 W
400 W
800 W

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SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)/60
Pmech = (ωT)/60
Pmech = (2πωT)
Pmech = ωT

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