SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

1200 W
800 W
1600 W
400 W

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SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)/60
Pmech = ωT
Pmech = (2πωT)
Pmech = (ωT)/60

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SSC JE Electrical 2019 with solution SET-1
 The resistive component of the rotor with resistance R2 offered to the backward rotating flux wave in a single-phase motor runs with slip s is given as

R2 ⁄ (1 + S)
R2 ⁄ (1 − S)
R2 ⁄ S
R2 ⁄ (2 − S)

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SSC JE Electrical 2019 with solution SET-1
 The amount of AC content present in the DC output of a rectifier is given by

Peak factor
Power factor
Form factor
Ripple factor

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