SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = ωT
Pmech = (ωT)/60
Pmech = (2πωT)/60
Pmech = (2πωT)

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SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

1600 W
400 W
800 W
1200 W

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SSC JE Electrical 2019 with solution SET-1
 A shaded pole motor is basically a motor

Single-phase induction
Shunt
Series
Synchronous

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SSC JE Electrical 2019 with solution SET-1
 In electric traction, the coefficient of adhesion is represented by

Φ
λ
γ
μ

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