SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)/60
Pmech = ωT
Pmech = (ωT)/60
Pmech = (2πωT)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 What would the total loss of the 2kVA transformer corresponding to maximum efficiency be, provided the transformer has the iron of 150 W and full-load copper loss of 250W?

500 W
300 W
400 W
100 W

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

1200 W
800 W
400 W
1600 W

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 The resistive component of the rotor with resistance R2 offered to the backward rotating flux wave in a single-phase motor runs with slip s is given as

R2 ⁄ (2 − S)
R2 ⁄ (1 − S)
R2 ⁄ S
R2 ⁄ (1 + S)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP