SSC JE Electrical 2019 with solution SET-1
 The direction of the arrow represents the direction of when the diode is forward biased

P-type material
N-type material
P-N Junction
Conventional current flow

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SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

1600 W
400 W
1200 W
800 W

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SSC JE Electrical 2019 with solution SET-1
 The laws involved in the expression e  = −dφ/dt are

Faraday’s and Ampere’s laws
Coulomb’s and Ampere’s laws
Coulomb’s and Faraday’s laws
Faraday’s and Lenz’s laws

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SSC JE Electrical 2019 with solution SET-1
 Lamp efficiency is measured in

Lumen/watt
Lux/watt
Lumen/lux
Candela/watt

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SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)/60
Pmech = ωT
Pmech = (2πωT)
Pmech = (ωT)/60

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