SSC JE Electrical 2019 with solution SET-1 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel 50 μF 0.1 μF 1 μF 100 μF 50 μF 0.1 μF 1 μF 100 μF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When the capacitance is connected in series the total capacitance is given byCeq = C1 + C2 + C3………CNCeq = 10nCeq =10 × 10 = 100 μF
SSC JE Electrical 2019 with solution SET-1 In the circuit shown, if R = 0, then the phase angle between v(t) and i(t) is 0° 60° 30° 90° 0° 60° 30° 90° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the given circuit if R = 0 then the circuit becomes purely inductive. So the phase angle between v(t) and i(t) is 90°.
SSC JE Electrical 2019 with solution SET-1 Identify the important feature of a DC series motor Zero starting torque Medium starting torque Low starting torque High starting torque Zero starting torque Medium starting torque Low starting torque High starting torque ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.
SSC JE Electrical 2019 with solution SET-1 Find the mutual inductance between two ideally coupled coils of 2H and 8H 4 H 2 H 16 H 8 H 4 H 2 H 16 H 8 H ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance between the two coils is K = √L1.L2K = √2 × 8k = √16k = 4 H
SSC JE Electrical 2019 with solution SET-1 Hunting occurs in a/an motor DC shunt DC series Synchronous Induction DC shunt DC series Synchronous Induction ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Sudden changes of load on synchronous motors may sometimes set up oscillations that are superimposed upon the normal rotation, resulting in periodic variations of a very low frequency in speed. This effect is known as hunting or phase-swinging.
SSC JE Electrical 2019 with solution SET-1 In the two wattmeter method, the readings of the two wattmeters are 500W, 500W respectively. The load power factor in a balanced 3-phase 3-wire circuit is: 1 0.9 0.8 0.5 1 0.9 0.8 0.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In two wattmeter method the phase angle is tanφ = √3(W1 − W2)/(W1 + W2) tanφ = √3(500 − 500)/(500 + 500) tanφ = 0° φ = tan−10° = 0° Power factor = cosφ PF = cos0° = 1
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