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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel

50 μF
1 μF
100 μF
0.1 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

When the capacitance is connected in series the total capacitance is given by
Ceq = C1 + C2 + C3………CN
Ceq = 10n
Ceq =10 × 10 = 100 μF
 

SSC JE Electrical 2019 with solution SET-1
 In the below circuit, X = ?

A + B
A.B
B
A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The circuit shown in the question is an AND GATE. In an AND gate has two or more inputs but it has only one output. An input signal applied to a gate has only two stable states, either 1 (HIGH) or 0 (LOW). In AND gate for any input A&B the output is A.B.
 


SSC JE Electrical 2019 with solution SET-1
 With the current direction marked in the circuit shown, the net voltage applied is

−(V2 − V1)
V1
(V2 − V1)
V2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Net voltage = −V2 + V1
Net voltage = −(V2 − V1)
 

SSC JE Electrical 2019 with solution SET-1
 Extension of moving iron ammeter range can be done by using

Capacitor
Inductor
Shunt
Multiplier

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
  ______starting method CANNOT be used for starting a 3-phase squirrel cage induction motor

Direct-on-line
Star-delta
Auto-transformer
Rotor-resistance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, the pressure coils of two wattmeters are connected to

Y
R
Neutral Wire
B

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In Two wattmeter method the current coils of the wattmeter are connected with any two lines, say R and Y and the potential coil of each wattmeter is joined across the same line, the third line i.e. B as shown below in the figure . In the circuit B is the common point for both the wattmeter.

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