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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel

50 μF
0.1 μF
100 μF
1 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

When the capacitance is connected in series the total capacitance is given by
Ceq = C1 + C2 + C3………CN
Ceq = 10n
Ceq =10 × 10 = 100 μF
 

SSC JE Electrical 2019 with solution SET-1
 Two inductors of 4H and 6H are connected in series. The equivalent inductance of this combination is

2.4 H
4 H
6 H
10 H

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total inductance when inductor are connected in series
L = L1 + L2
L = 4 + 6 =10H
 

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

10 Ω
1 Ω
2 Ω
5 Ω

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

From the figure it can be concluded that the voltmeter reads 5 volts as shown in the figure below. Based on the voltmeter and ammeter readings in the measuring network, determine the value of the resistor R Here Current I = 1/2 A = 0.5 A Voltage V = 5 V R = V/I = 0.5/5 R = 10Ω


SSC JE Electrical 2019 with solution SET-1
 The function of condenser in a Thermal power plant is:

Condense water
Purify steam
Condense used steam into water
Purify water

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SSC JE Electrical 2019 with solution SET-1
 Identify the important feature of a DC series motor

Medium starting torque
Low starting torque
High starting torque
Zero starting torque

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.

SSC JE Electrical 2019 with solution SET-1
 The power factor of an A.C. circuit is equal to

R/XC
Z/R
R/Z
R/XL

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In electrical engineering, the power factor of an AC electrical power system is defined as the ratio of the real power flowing to the load to the apparent power in the circuit ” R/Z”.
 

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