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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 With the current direction marked in the circuit shown, the net voltage applied is

V1
−(V2 − V1)
V2
(V2 − V1)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Net voltage = −V2 + V1
Net voltage = −(V2 − V1)
 

SSC JE Electrical 2019 with solution SET-1
 _____ power plant is the plant which uses a non-conventional source of energy

Hydroelectric
Nuclear
Wind
Thermal

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SSC JE Electrical 2019 with solution SET-1
 Prevention of interference with neighboring telephone lines can be done by:

Reducing corona
Reducing skin effect
Transposing transmission lines
Using bundled conductors

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SSC JE Electrical 2019 with solution SET-1
 A 200 V d.c machine as Ra = 0.5 Ω and its full-load Ia= 20A. Determine the induced e.m.f when the machine acts as a motor

200 V
215 V
210 V
190 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given Data
Voltage Va = 200 v
Armature Resistance Ra = 0.5Ω
Armature Current Ia = 20 A
Induced EMF = Ea = ?
The Induced EMF of a DC machine working as a Motor is
Ea = Va − IaRa
Ea = 200 − 20 × 0.5
Ea = 190 V

SSC JE Electrical 2019 with solution SET-1
 Extension of moving iron ammeter range can be done by using

Shunt
Inductor
Multiplier
Capacitor

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SSC JE Electrical 2019 with solution SET-1
 When the only current source is active in the circuit, find the current through the 10Ω resistor

1.33 A
0.66 A
1.66 A
0 A

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