• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 With the current direction marked in the circuit shown, the net voltage applied is

V1
−(V2 − V1)
V2
(V2 − V1)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Net voltage = −V2 + V1
Net voltage = −(V2 − V1)
 

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

2 Ω
5 Ω
10 Ω
1 Ω

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

From the figure it can be concluded that the voltmeter reads 5 volts as shown in the figure below. Based on the voltmeter and ammeter readings in the measuring network, determine the value of the resistor R Here Current I = 1/2 A = 0.5 A Voltage V = 5 V R = V/I = 0.5/5 R = 10Ω


SSC JE Electrical 2019 with solution SET-1
 Two coupled coils with L1 = L2 = 0.5H have a coupling coefficient of K = 0.75. The turn ratio N1 ⁄ N2 = ?

1
4
2
0.5

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The self-inductance is given as
L = μN2A/I
L ∝ N2
where
N is the number of turns of the solenoid
A is the area of each turn of the coil
l is the length of the solenoid
and μ is the permeability constant
L1/L2 = N21/N22
0.5/0.5 = N21/N22
N1/N2 = 1
 

SSC JE Electrical 2019 with solution SET-1
 The direction of the arrow represents the direction of when the diode is forward biased

P-type material
Conventional current flow
N-type material
P-N Junction

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The direction of the arrow represents the direction of the conventional current flow when the diode is forward biased.
 

SSC JE Electrical 2019 with solution SET-1
 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches

Cos 10°
Cos 45°
Cos 30°
Cos 60°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Coil Span = 8
Pole Pitch = 9 slots/pole
Slot angle (α) = 180° / Pole Pitch = 180°/9 = 20°
Pitch Factor = cos(α/2) = cos (20/2)
Pitch Factor = cos 10°
 

SSC JE Electrical 2019 with solution SET-1
 Which of the following fuel has the least calorific value?

Wood
Hydrogen
LPG
Kerosene oil

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In the above option, the wood has the lowest calorific value. Its value is around 17000 – 20000 kilojoule/kg.
The calorific value of LPG is 55000 kilojoule/kg.
The calorific value of Kerosene oil is 45000 kilojoule/kg.
The calorific value of hydrogen oil is 150000 kilojoule/kg.
 

MORE MCQ ON SSC JE Electrical 2019 with solution SET-1

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑