Theory of Machine The frictional torque transmitted in a conical pivot bearing with assumption of uniform pressure is __________ as compared to uniform wear. More Less Same None of these More Less Same None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The engine of an aeroplane rotates in clockwise direction when seen from the tail end and the aeroplane takes a turn to the left. The effect of gyroscopic couple on the aeroplane will be To dip the nose and raise the tail To raise the nose and dip the tail To raise the nose and tail To dip the nose and tail To dip the nose and raise the tail To raise the nose and dip the tail To raise the nose and tail To dip the nose and tail ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A shaft has two heavy rotors mounted on it. The transverse natural frequencies, considering each of the rotor separately, are 100 Hz and 200 Hz respectively. The lowest critical speed is 12,000 r.p.m. 6,000 r.p.m. 5,367 r.p.m. 9,360 r.p.m. 12,000 r.p.m. 6,000 r.p.m. 5,367 r.p.m. 9,360 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For an isochronous Hartnell governor (where r₁ and r₂ = Maximum and minimum radius of rotation of balls respectively, S₁ and S₂ = Maximum and minimum force exerted on the sleeve respectively, and M = Mass on the sleeve) S₂/S₁ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ S₁/S₂ = r₁/r₂ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ S₁/S₂ = r₁/r₂ (m.g + S₁)/(m.g + S₂) = r₁/r₂ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 2(l - 1) - 2j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The equivalent length of a simple pendulum which gives the same frequency as a compound pendulum is h/(kG² + h²) h²/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h/(kG² + h²) h²/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h ANSWER DOWNLOAD EXAMIANS APP
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