Hydraulics and Fluid Mechanics in ME The flow in which the particles of a fluid attain such velocities that vary from point to point in magnitude and direction as well as from instant to instant, is known as uniform flow one dimensional flow turbulent flow steady flow uniform flow one dimensional flow turbulent flow steady flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A one dimensional flow is one which is steady uniform flow involves zero transverse component of flow takes place in straight lines is uniform flow is steady uniform flow involves zero transverse component of flow takes place in straight lines is uniform flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular notch is Directly proportional to H3/2 Inversely proportional to H3/2 Inversely proportional to H5/2 Directly proportional to H5/2 Directly proportional to H3/2 Inversely proportional to H3/2 Inversely proportional to H5/2 Directly proportional to H5/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a right angled notch is (where H = Height of liquid above the apex of notch) (8/15) Cd. 2g. H (8/15) Cd. 2g. H3/2 (8/15) Cd. 2g. H² (8/15) Cd. 2g. H5/2 (8/15) Cd. 2g. H (8/15) Cd. 2g. H3/2 (8/15) Cd. 2g. H² (8/15) Cd. 2g. H5/2 ANSWER DOWNLOAD EXAMIANS APP
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