Hydraulics and Fluid Mechanics in ME The efficiency of a hydraulic press is given by (where W = Weight lifted by ram, P = Force applied on plunger, A = Area of ram, and a = Area of plunger) (p/W) × (A/a) (W/p) × (a/A) (W/p) × (A/a) (p/W) × (a/A) (p/W) × (A/a) (W/p) × (a/A) (W/p) × (A/a) (p/W) × (a/A) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The most economical section of a trapezoidal channel is one which has hydraulic mean depth equal to 1/4 × (depth + breadth) 1/2 × breadth 1/2 × sloping side 1/2 × depth 1/4 × (depth + breadth) 1/2 × breadth 1/2 × sloping side 1/2 × depth ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The property of a fluid which enables it to resist tensile stress is known as compressibility surface tension adhesion cohesion compressibility surface tension adhesion cohesion ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If the surface of liquid is convex, men Cohesion pressure is negligible Cohesion pressure is decreased There is no cohesion pressure Cohesion pressure is increased Cohesion pressure is negligible Cohesion pressure is decreased There is no cohesion pressure Cohesion pressure is increased ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Head developed by a centrifugal pump is Proportional to diameter and speed of impeller Proportional to diameter of impeller None of these Proportional to speed of impeller Proportional to diameter and speed of impeller Proportional to diameter of impeller None of these Proportional to speed of impeller ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] ANSWER DOWNLOAD EXAMIANS APP
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