Hydraulics and Fluid Mechanics in ME
A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

2A × (√H₁ - √H₂)/Cd × a × √(2g)
2A × √H₂/Cd × a × √(2g)
2A × √H₁/Cd × a × √(2g)
2A × (√H3/2 - √H3/2)/Cd × a × √(2g)

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Hydraulics and Fluid Mechanics in ME
The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge)

Q = (2/3) Cd × b × √(2g) × (H2 - H1)
Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2)
Q = (2/3) Cd × b × √(2g) × (H22 - H12)
Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2)

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