Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Bernoulli's equation Z + p/w + v²/2g = constant Z + p/w - v²/2g = constant Z - p/w + v²/2g = constant Z - p/w - v²/2g = constant Z + p/w + v²/2g = constant Z + p/w - v²/2g = constant Z - p/w + v²/2g = constant Z - p/w - v²/2g = constant ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth of the centre of pressure on a vertical rectangular gate 8 m wide and 6 m high, when the water surface coincides with the top of the gate, is 3.0 m 4.0 m 5.0 m 2.4 m 3.0 m 4.0 m 5.0 m 2.4 m ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The major loss of energy in long pipes is due to gradual contraction or enlargement sudden contraction sudden enlargement friction gradual contraction or enlargement sudden contraction sudden enlargement friction ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Whenever a plate is held immersed at some angle with the direction of flow of the liquid, it is subjected to some pressure. The component of this pressure, in the direction of flow of the liquid, is known as Bulk modulus Lift Drag Stagnation pressure Bulk modulus Lift Drag Stagnation pressure ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A vertically immersed surface is shown in the below figure. The distance of its centre of pressure from the water surface is b²/12 + x̅ (d²/12 x̅) + x̅ (bd²/12) + x̅ d²/12 + x̅ b²/12 + x̅ (d²/12 x̅) + x̅ (bd²/12) + x̅ d²/12 + x̅ ANSWER DOWNLOAD EXAMIANS APP
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