Hydraulics and Fluid Mechanics in ME
A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

2A × (√H₁ - √H₂)/Cd × a × √(2g)
2A × √H₂/Cd × a × √(2g)
2A × √H₁/Cd × a × √(2g)
2A × (√H3/2 - √H3/2)/Cd × a × √(2g)

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Hydraulics and Fluid Mechanics in ME
The total energy of a liquid particle in motion is equal to

Pressure energy - (kinetic energy + potential energy)
Pressure energy + kinetic energy + potential energy
Potential energy - (pressure energy + kinetic energy
Kinetic energy - (pressure energy + potential energy)

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Hydraulics and Fluid Mechanics in ME
When an ideal fluid flows past a sphere

lowest pressure intensity occurs at rear stagnation point
lowest pressure intensity occurs at front stagnation point
total drag is zero
highest intensity of pressure occurs around the circumference at right angles to flow

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