Area Problems The diameter of a circle is 105 cm less than the circumference. What is the diameter of the circle? 44 cm 48 cm 49 cm 46 cm 44 cm 48 cm 49 cm 46 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ?d-d = 105 cm ? (? -1 ) d = 105 cm? [(22/7)-1] x d = 105 cm? d = (7/15) x 105 cm = 49 cm
Area Problems In ? ABC ,sides BC = 10 cm and height AD = 4.4 cm. If AC = 11 cm. Then altitude BE equals? 5.5 cm 4 cm 5 cm 5.6 cm 5.5 cm 4 cm 5 cm 5.6 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We know that area of triangle = ( base x height ) / 2So area of triangle = (BC x AD) / 2 = (AC x BE) / 2 ? (10 x 4.4) / 2 = (11 x h) / 2? h= (10 x 4.4)/11 = 4 cm
Area Problems The ratio of the area of square of side a and equilateral triangle of side a is? 4 : ?3 2 : ?3 4 :3 2 :1 4 : ?3 2 : ?3 4 :3 2 :1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of area = a2/ ?(3/4) a2= 4/?3 = 4:?3
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 34 88 68 40 34 88 68 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
Area Problems In a circle of radius 21 cm an arc subtends an angle of 72° at the centre. The length of the arc is? 26.4 cm 19.8 cm 21.6 cm 13.2 cm 26.4 cm 19.8 cm 21.6 cm 13.2 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Arc length = 2?r (?° / 360°) = 2 x (22/7) x 21 x (72° / 360°) cm= 26.4 cm
Area Problems A wheel make 4000 revolution in moving a distance of 44 km. Find the radius of the wheel. 25 m 28 m 27 m 1.75 m 25 m 28 m 27 m 1.75 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in 1 revolution = (44 x 1000) / 4000 = 11 mAccording to the question, 2?r = 11 ? (44/7) x r = 11? r = (11 x 7) / 44 = 1.75 m
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