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Engineering Mechanics

Engineering Mechanics
The centre of gravity a T-section 100 mm × 150 mm × 50 mm from its bottom is

125 mm
50 mm
87.5 mm
75 mm

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Engineering Mechanics
The center of gravity of a semi-circle lies at a distance of __________ from its base measured along the vertical radius.

4r/ 3π
3r/4π
8r/3
3r/ 8

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Engineering Mechanics
The unit of work in S.I. units is

joule
kg-m
erg
Newton

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Engineering Mechanics
The moment of inertia of a square of side (a) about an axis through its center of gravity is

a4/4
a4/8
a4/12
a4/36

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Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG + Ah2
IP = IG / Ah2
IP = Ah2 / IG
IP = IG - Ah2

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Engineering Mechanics
In order to determine the effects of a force, acting on a body, we must know

All of these
Nature of the force i.e. whether the force is push or pull
Magnitude of the force
Line of action of the force

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