Engineering Mechanics The centre of gravity a T-section 100 mm × 150 mm × 50 mm from its bottom is 125 mm 75 mm 50 mm 87.5 mm 125 mm 75 mm 50 mm 87.5 mm ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a solid cylinder of mass 'm', radius 'r' and length 'l' about the longitudinal axis or polar axis is mr²/8 mr²/2 mr²/4 mr²/6 mr²/8 mr²/2 mr²/4 mr²/6 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The force, by which the body is attracted, towards the center of the earth, is called Mass Momentum Impulsive force Weight Mass Momentum Impulsive force Weight ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a thin spherical shell of mass m and radius r, about its diameter is 3mr²/5 2mr²/3 2mr²/5 mr²/3 3mr²/5 2mr²/3 2mr²/5 mr²/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Angle of friction is the The ratio of minimum friction force to friction force acting when the body is in motion The ratio of minimum friction force to the friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and the resultant of normal reaction and the limiting friction The ratio of minimum friction force to friction force acting when the body is in motion The ratio of minimum friction force to the friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and the resultant of normal reaction and the limiting friction ANSWER DOWNLOAD EXAMIANS APP
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