Engineering Mechanics The centre of gravity a T-section 100 mm × 150 mm × 50 mm from its bottom is 75 mm 125 mm 50 mm 87.5 mm 75 mm 125 mm 50 mm 87.5 mm ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/36 a4/12 a4/4 a4/8 a4/36 a4/12 a4/4 a4/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a rectangular section 3 cm wide and 4 cm deep about X-X axis is 20 cm4 12 cm4 9 cm4 16 cm4 20 cm4 12 cm4 9 cm4 16 cm4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a solid cone of mass ‘m’ and base radius ‘r’ about its vertical axis is 4mr²/5 3mr²/10 3mr²/5 2mr²/5 4mr²/5 3mr²/10 3mr²/5 2mr²/5 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The total momentum of a system of masses (i. e. moving bodies) in any one direction remains constant, unless acted upon by an external force in that direction. This statement is called Newton's first law of motion Newton's second law of motion Principle of conservation of momentum Principle of conservation of energy Newton's first law of motion Newton's second law of motion Principle of conservation of momentum Principle of conservation of energy ANSWER DOWNLOAD EXAMIANS APP
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