Engineering Mechanics The maximum acceleration of a particle moving with simple harmonic motion is ω ω/r ω²r ωr ω ω/r ω²r ωr ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A weight of 1000 N can be lifted by an effort of 80 N. If the velocity ratio is 20, the machine is Ideal None of these Non-reversible Reversible Ideal None of these Non-reversible Reversible ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.) P = W tanα P = W tan (α + φ) P = W (sinα + μcosα) P = W (cosα + μsinα) P = W tanα P = W tan (α + φ) P = W (sinα + μcosα) P = W (cosα + μsinα) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A block of mass 20 kg lying on a rough horizontal plane is connected by a light string passing over a smooth pulley to another mass 5 kg, which can move freely in the Vertical direction, as shown in the below figure. The tension in the string will ___________ with the increase in coefficient of friction. Increase None of these Not be effected Decrease Increase None of these Not be effected Decrease ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum velocity of a particle moving with simple harmonic motion is ω ω/r ω2r ωr ω ω/r ω2r ωr ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P/m.a = 0 P - m.a = 0 P × m.a = 0 P + m.a = 0 P/m.a = 0 P - m.a = 0 P × m.a = 0 P + m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
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