Engineering Mechanics The maximum acceleration of a particle moving with simple harmonic motion is ω²r ωr ω ω/r ω²r ωr ω ω/r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the width (b), is bd³/12 bd³/36 db³/36 db³/12 bd³/12 bd³/36 db³/36 db³/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Static friction is always __________ dynamic friction. None of these Equal to Greater than Less than None of these Equal to Greater than Less than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to completely specify angular displacement by a vector, it must fix All of these Sense of angular displacement Magnitude of angular displacement Direction of the axis of rotation All of these Sense of angular displacement Magnitude of angular displacement Direction of the axis of rotation ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of two equal forces ‘P’ making an angle ‘θ’, is given by 2P sinθ/2 2P tanθ/2 2P cotθ/2 2P cosθ/2 2P sinθ/2 2P tanθ/2 2P cotθ/2 2P cosθ/2 ANSWER DOWNLOAD EXAMIANS APP
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