Engineering Mechanics If rain is falling in the opposite direction of the movement of a pedestrian, he has to hold his umbrella More inclined when moving Less inclined when moving More inclined when standing Less inclined when standing More inclined when moving Less inclined when moving More inclined when standing Less inclined when standing ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a solid cylinder of mass 'm', radius 'r' and length 'l' about the longitudinal axis or polar axis is mr²/8 mr²/4 mr²/2 mr²/6 mr²/8 mr²/4 mr²/2 mr²/6 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a sphere of mass 'm' and radius 'r', about an axis tangential to it, is 2mr²/5 7mr²/5 7mr²/3 2mr²/3 2mr²/5 7mr²/5 7mr²/3 2mr²/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a solid cone of mass ‘m’ and base radius ‘r’ about its vertical axis is 4mr²/5 3mr²/5 2mr²/5 3mr²/10 4mr²/5 3mr²/5 2mr²/5 3mr²/10 ANSWER DOWNLOAD EXAMIANS APP
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