MGVCL Exam Paper (30-07-2021 Shift 2) Recently, which country has withdrawn the 'Generalized System of Preferences' with India? United States of America Pakistan Peru Russia United States of America Pakistan Peru Russia ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circular loop has its radius increasing at a rate of 2 m/s. The loop is placed perpendicular to a constant magnetic field of 0.1 Wb/m². When the radius of the loop is 2 m, the emf induced in the loop will be 0.8π V zero 0.4π V 0.2π V 0.8π V zero 0.4π V 0.2π V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP emf = dΨ/dt = change of flux linkageemf = dф/dtemf = d(B*Area)/dtemf = B*d(area)/dtemf = B*d(πr²)/dtemf = Bπ*2r*dr/dtemf = Bπ*2r*change of radius per unit timeemf = 0.1*π*2*2emf = 4π
MGVCL Exam Paper (30-07-2021 Shift 2) The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is E = V/d E = V x d E = V/(d)² E = Vx(d)² E = V/d E = V x d E = V/(d)² E = Vx(d)² ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is given by:V = E*LE = V/L
MGVCL Exam Paper (30-07-2021 Shift 2) જે ક્રિયા દર્શાવે પણ વાક્યનો અર્થ પૂર્ણ કરે એ એને ____કહેવાય. - આપેલ વિકલ્પોમાંથી યોગ્યનું ચયન કરી વાક્ય પૂર્ણ કરો વિભક્તિ ક્રિયા-વિભક્તિ કૃદંત નીપાત વિભક્તિ ક્રિયા-વિભક્તિ કૃદંત નીપાત ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 75 km to 100 km 10 km to 15 km 30 km to 60 km 20 to 25 km 75 km to 100 km 10 km to 15 km 30 km to 60 km 20 to 25 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 12 kV, 50 Hz and 300 kW load is operating at 0.8 pf lag. If the pf is to be improved to unity, using star connected capacitor, the per phase value of the reactive VAR required is: 100 kVAR 75 kVAR 50 kVAR 25 kVAR 100 kVAR 75 kVAR 50 kVAR 25 kVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The reactive VAR required = kW*(tanφ1 -tanφ2)Cosφ1 = 0.8φ1 = 36.87 deg.Cosφ2 = 0φ2 = 0 deg.kVAR required = kW*(tan(36.87) - tan(0))= 300*1000(0.75)= 225.00 kVARPer phase value = 225.00/3= 75 kVAR
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