MGVCL Exam Paper (30-07-2021 Shift 2) Recently, which country has withdrawn the 'Generalized System of Preferences' with India? Peru Pakistan United States of America Russia Peru Pakistan United States of America Russia ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors).(A) The Manager, with / (B) all his employee, was / (C) fired from the company /(D) NO ERROR D A C B D A C B ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Recently, India and Benin signed MoUs on education, health and ____ Against Corruption e-visa facilities Trading Defence Against Corruption e-visa facilities Trading Defence ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase motor connected to 415 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging. 86.32 µF 76.32 µF 66.32 µF 96.32 µF 86.32 µF 76.32 µF 66.32 µF 96.32 µF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = VIcosφ = 8715 wattQ = VAR required to improve PF = P(tanφ₁ - tanφ₂) = 4670 VARCapacitive Reactance, Xc = V²/Q = 36.8790 ohm.C = (2πfXc)⁻¹ = 86.314 μF
MGVCL Exam Paper (30-07-2021 Shift 2) If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be 9 × 10⁸ m/s 27 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s 9 × 10⁸ m/s 27 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Speed of EM wave in medium = C/√(εr*μr)= (300000000)/√9= 300000000/3= 100000000= 1*10⁸ m/s
MGVCL Exam Paper (30-07-2021 Shift 2) In the RLC series circuit shown in figure, resonance occurs when the value of C is 20 µF. The supply voltages is v(t) = 20 sin (500t) V. Find the value of L. 5 H 5 mH 0.2 H 0.2 mH 5 H 5 mH 0.2 H 0.2 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,ω = 500 rad/sec = 2πf.At Resonance condition,ωL = 1/(ωC)L 0.2 HAlso at series resonace1. fr = 1/[2π√(LC)]2. PF = 13. Maximum current4. Source voltage = voltage across resistor.
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