Power Systems The sequence components of the fault current are as follows: IR1 = j1.5 pu, IR2 = -j0.5 pu, IR0 = -j1. The type of fault is LLG LG LL LLL LLG LG LL LLL ANSWER DOWNLOAD EXAMIANS APP
Power Systems The pu parameters for a 500 MVA machine on its own base are: Inertia, H = 20 pu; reactance X = 2 pu. The pu values of inertia and reactance on 100 MVA common base, respectively, are 100, 0.4 4, 0.4 4, 10 100, 10 100, 0.4 4, 0.4 4, 10 100, 10 ANSWER DOWNLOAD EXAMIANS APP
Power Systems An isolated synchronous generator with transient reactance equal to 0.1 pu on a 100 MVA base is connected to the high voltage bus through a step up transformer of reactance 0.1 pu on a 100 MVA base. The fault level at the bus is 100 MVA 500 MVA 200 MVA 400 MVA 100 MVA 500 MVA 200 MVA 400 MVA ANSWER DOWNLOAD EXAMIANS APP
Power Systems An over current relay, having a current setting of 125% connected to a supply circuit through a current transformer of ratio 400/5. The pick up value is 6.25 A 15 A 10 A 12.5 A 6.25 A 15 A 10 A 12.5 A ANSWER DOWNLOAD EXAMIANS APP
Power Systems An over current relay, having a current setting of 125% connected to a supply circuit through a current transformer of ratio 500/5. The plug setting multiplier for a fault current of 5 kA is 6 8 2 5 6 8 2 5 ANSWER DOWNLOAD EXAMIANS APP
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