Engineering Mechanics One kg force is equal to 12 N 7.8 N 9.8 N 8.9 N 12 N 7.8 N 9.8 N 8.9 N ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its C.G. and parallel to the depth (d), is bd³/12 db³/36 bd³/36 db³/12 bd³/12 db³/36 bd³/36 db³/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Centre of gravity of a solid cone lies on the axis at the height One fourth of the total height above base Three eighth of the total height above the base One third of the total height above base One-half of the total height above base One fourth of the total height above base Three eighth of the total height above the base One third of the total height above base One-half of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum frictional force, which comes into play, when a body just begins to slide over the surface of the other body, is known as Limiting friction Coefficient of friction Dynamic friction Static friction Limiting friction Coefficient of friction Dynamic friction Static friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A smooth cylinder lying on a __________ is in neutral equilibrium. Curved surface None of these Horizontal surface Convex surface Curved surface None of these Horizontal surface Convex surface ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS