Engineering Mechanics One kg force is equal to 8.9 N 7.8 N 12 N 9.8 N 8.9 N 7.8 N 12 N 9.8 N ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The algebraic sum of the resolved parts of a number of forces in a given direction is equal to the resolved part of their resultant in the same direction. This is known as Principle of independence of forces Principle of resolution of forces None of these Principle of transmissibility of forces Principle of independence of forces Principle of resolution of forces None of these Principle of transmissibility of forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A cable with a uniformly distributed load per horizontal meter run will take the following shape Elliptical Hyperbola Parabola Straight line Elliptical Hyperbola Parabola Straight line ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as -9.8 m/s2 +9.8 m/s2 +8.9 m/s2 -8.9 m/s2 -9.8 m/s2 +9.8 m/s2 +8.9 m/s2 -8.9 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If u₁ and u₂ are the velocities of two moving bodies in the same direction before impact and v₁ and v₂ are their velocities after impact, then coefficient of restitution is given by (v₂ - v₁)/(u₁ - u₂) (u₁ - u₂)/(v₁ - v₂) (v₁ - v₂)/(u₁ - u₂) (u₂ + u₁)/(v₂ + v₁) (v₂ - v₁)/(u₁ - u₂) (u₁ - u₂)/(v₁ - v₂) (v₁ - v₂)/(u₁ - u₂) (u₂ + u₁)/(v₂ + v₁) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS