Engineering Mechanics The process of finding out the resultant force is called __________ of forces. Composition None of these Resolution Decomposition Composition None of these Resolution Decomposition ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its vertex and parallel to the base, is __________ than that passing through its C.G. and parallel to the base. Two times Nine times Four times Six times Two times Nine times Four times Six times ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Slant down towards direction of pull Slant up towards direction of pull None of these Remain horizontal Slant down towards direction of pull Slant up towards direction of pull None of these Remain horizontal ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of a uniform lamina lies at The midpoint of its axis The bottom surface All of these The centre of heavy portion The midpoint of its axis The bottom surface All of these The centre of heavy portion ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The energy possessed by a body, for doing work by virtue of its position, is called Chemical energy Electrical energy Kinetic energy Potential energy Chemical energy Electrical energy Kinetic energy Potential energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
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