Process Equipment and Plant Design Movement of pipeline caused by thermal expansion is taken care by providing Changes in its direction Expansion joint All of these Change in the shape of pipeline Changes in its direction Expansion joint All of these Change in the shape of pipeline ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Power required for agitation depends upon the All of these Size of agitator & the tank Agitator type & speed of agitation Height & properties of the liquid All of these Size of agitator & the tank Agitator type & speed of agitation Height & properties of the liquid ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The normal range of velocity of steam in pipes is __________ m/sec. 10-20 0.1-0.5 1-5 80-100 10-20 0.1-0.5 1-5 80-100 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The minimum baffle height should be 3/4 of the tank height Equal to the impeller diameter Twice the tank diameter Twice the impeller diameter 3/4 of the tank height Equal to the impeller diameter Twice the tank diameter Twice the impeller diameter ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Pick out the wrong statement about routing of fluids in a shell and tube heat exchanger. The viscous fluid should be routed through the shell side Lower flow rate fluid should be routed through the shell side The corrosive and fouling fluid should be preferably routed through the tubes Higher pressure fluid stream should be routed through the shell side The viscous fluid should be routed through the shell side Lower flow rate fluid should be routed through the shell side The corrosive and fouling fluid should be preferably routed through the tubes Higher pressure fluid stream should be routed through the shell side ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Heat transfer co-efficient, hG(Kcal/hr.m² .°C) and mass velocity of air, G (kg/hr.m² ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to 1.004G0.8 0.0176G1.37 HG = 0.0176G0.37 HG = 1.004G0.37 1.004G0.8 0.0176G1.37 HG = 0.0176G0.37 HG = 1.004G0.37 ANSWER DOWNLOAD EXAMIANS APP
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