Machine Design Maximum principal stress theory is applicable for Elastic materials Ductile materials All of these Brittle materials Elastic materials Ductile materials All of these Brittle materials ANSWER DOWNLOAD EXAMIANS APP
Machine Design The dedendum circle diameter is equal to (where φ = Pressure angle) Clearance circle diameter × cosφ Pitch circle diameter × cosφ Addendum circle diameter × cosφ Pitch circle diameter × sinφ Clearance circle diameter × cosφ Pitch circle diameter × cosφ Addendum circle diameter × cosφ Pitch circle diameter × sinφ ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the shaft rotates in anticlockwise direction at high speed in a bearing, it will Move towards right of the bearing making no metal to metal contact Have contact at the bottom most of the bearing Move towards right of the bearing making metal to metal contact Move towards left of the bearing making metal to metal contact Move towards right of the bearing making no metal to metal contact Have contact at the bottom most of the bearing Move towards right of the bearing making metal to metal contact Move towards left of the bearing making metal to metal contact ANSWER DOWNLOAD EXAMIANS APP
Machine Design The stress in the bar when the load is applied suddenly is __________ as compared to the stress induced due to gradually applied loads. Same Four times Three times Double Same Four times Three times Double ANSWER DOWNLOAD EXAMIANS APP
Machine Design A stud Has both the ends threaded Has pointed threads Has a head on one end and a nut fitted to the other Has head at one end and other end fits into a tapped hole in the other part to be joined Has both the ends threaded Has pointed threads Has a head on one end and a nut fitted to the other Has head at one end and other end fits into a tapped hole in the other part to be joined ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to maximum normal stress theory, the maximum normal stress in the shaft is σ + √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] √(σ² × 4τ²) σ + √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] √(σ² × 4τ²) ANSWER DOWNLOAD EXAMIANS APP
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